1. Consider the reaction 2H3PO4P2O5+3H2O Using the information in the following
ID: 715188 • Letter: 1
Question
1. Consider the reaction
2H3PO4P2O5+3H2O
Using the information in the following table, calculate the average rate of formation of P2O5 between 10.0 and 40.0 s.
Express your answer with the appropriate units.
Determine the average rate of decomposition of H3PO4 between 10.0 and 40.0 s.
Express your answer with the appropriate units.
Rate of decomposition of H3PO4 = ?
2. Consider the reaction
5Br(aq)+BrO3(aq)+6H+(aq)3Br2(aq)+3H2O(l)
The average rate of consumption of Br is 1.26×104M/s over the first two minutes. What is the average rate of formation of Br2 during the same time interval?
Express your answer with the appropriate units.
What is the average rate of consumption of H+ during the same time interval?
Rate of consumption of H+ = ?
3. For a higher temperature, the curve would be For a higher temperature, the curve would be ______ spread out, the maximum of the curve would be _____ and to the ______ of the maximum of the red curve, and a _____ fraction of molecules would have kinetic energy greater than Ea than for the red curve.
Choices:
More, smaller, lower, right, left, greater, less, higher
Time (s) 0 10.0 20.0 30.0 40.0 50.0 [P2O5] (M) 0 1.70×103 4.70×103 6.50×103 7.70×103 8.30×103Explanation / Answer
1)
average rate of formation of P2O5 = change in concentration of P2O5 / change in time
= (C2-C1) / (t2-t1)
= (7.70*10^-3 - 1.70*10^-3) / (40.0-10.0)
= 6.00*10^-3 M / 30.0 s
= 2.00*10^-4 M/s
Answer: 2.00*10^-4 M/s
2)
Rate of reaction in terms of Br- is:
rate of reaction = (1/5)*rate of consumption of Br-
Rate of reaction in terms of Br2 is:
rate of reaction = (1/3)*rate of production of Br2
equate both rate of reaction:
(1/3)*rate of production of Br2 = (1/5)*rate of consumption of Br-
rate of production of Br2 = (3/5)*rate of consumption of Br-
= (3/5)*(1.26*10^-4 M/s)
= 7.56*10^-5 M/s
Answer: 7.56*10^-5 M/s
similarly:
rate of consumption of H+ = (6/5)*rate of consumption of Br-
= (6/5)*(1.26*10^-4 M/s)
= 1.51*10^-4 M/s
Answer: 1.51*10^-4 M/s
For 3rd question there is missing diagram.
It is talking about red curve.
please ad them
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