calculate the standard state entropy for the following reaction 6Co2(g)+6H2O= c6

Question

calculate the standard state entropy for the following reaction 6Co2(g)+6H2O= c6H12aO(s)+6O2 Part B Calculate the standard-state entropy for the following reaction: 6 CO2(g) +6 H20(g) 1 CoH120s(s) + 6 02(g) (If applicable, coefficients of one have been included for clarity.) The standard entropy values are given in the table. So Formula /(K .mol) CeH1206 (s) 212 205 214 H20(g)189 02(g) CO2(g) Express your answer with the appropriate units. You did not open hints for this part. ANSWER Entropy and the Second Law of Thermodynamics- Copy ho cerond law of thermodynamics, all reactions proceed spontaneously in the direction that increases total er

Explanation / Answer

Given:

Sof(CO2(g)) = 214.0 J/mol.K

Sof(H2O(g)) = 189.0 J/mol.K

Sof(C6H12O6(s)) = 212.0 J/mol.K

Sof(O2(g)) = 205.0 J/mol.K

Balanced chemical equation is:

6 CO2(g) + 6 H2O(g) ---> C6H12O6(s) + 6 O2(g)

So rxn = 1*Sof(C6H12O6(s)) + 6*Sof(O2(g)) - 6*Sof( CO2(g)) - 6*Sof(H2O(g))

So rxn = 1*(212.0) + 6*(205.0) - 6*(214.0) - 6*(189.0)

So rxn = -976 J/K

Answer: -976 J/K

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