What is the net ionic equation when NaBr and AgNO 3 are mixed? Na+ (aq) + Br - (

Question

What is the net ionic equation when NaBr and AgNO3 are mixed?

Na+(aq) + Br-(aq) + Ag+(aq) + NO3-(aq) --> Na+(aq) + Br-(aq) + Ag+(aq) + NO3-(aq)

Na+(aq) + Br-(aq) + Ag+(aq) + NO3-(aq) --> Na+(aq) + NO3-(aq) + AgBr(s)

Na+(aq) + NO3-(aq) --> NaNO3(s)

Ag+(aq) + Br-(aq) -->  AgBr(s)

Na+(aq) + Br-(aq) + Ag+(aq) + NO3-(aq) --> Na+(aq) + Br-(aq) + Ag+(aq) + NO3-(aq)

Na+(aq) + Br-(aq) + Ag+(aq) + NO3-(aq) --> Na+(aq) + NO3-(aq) + AgBr(s)

Na+(aq) + NO3-(aq) --> NaNO3(s)

Ag+(aq) + Br-(aq) -->  AgBr(s)

Explanation / Answer

AgBr will be precipitate formed in the reaction

we have below given equation

NaBr (aq) + AgNO3 (aq) --> AgBr (s) + NaNO3 (aq)

Total ionic equation is

Spectator ions should not be removed here. Spectator ions are part of total ionic equation

Na+ (aq) + Br- (aq) + Ag+ (aq) + NO3- (aq) --> AgBr (s) + Na+ (aq) + NO3- (aq)

Spectator ions should be removed now. Spectator ions are not part of total ionic equation

After removing Spectator ions, net ionic equation is:

Ag+ (aq) + Br- (aq) --> AgBr (s)

Answer: option 4

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