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1. Silver chlo ride is not soluble in water. What are the relative strengths of

ID: 713823 • Letter: 1

Question

1. Silver chlo ride is not soluble in water. What are the relative strengths of the intermolecular forces between Ag' ons and water molecules as compared to the intermolecular forces between water molecules and the e ionic attractions are stronger than the polar covalent bonds between the H' and O2 ions of the b. The ionic attractions are weaker than the intermolecular forces between the Ag' and Cr ions and water c. The ionic attractions are stronger than the intermolecular forces between the Ag' and Cr ions and wate d. The ionic attractions are the same as the intermolecular forces between the Ag' and Cr ions and water and Cl-i forces that hold the silver chloride as a solid? water molecules. molecules molecules. molecules

Explanation / Answer

1. the solubility of a salt will be depends on two factors mainly (1) the lattice energy, the energy required to break the ionic solid apart into separated ions, and (2) the hydration energy, the energy released when the separated ions become surrounded by water molecules,  solubility will be favored only if there is a net release of energy, that is, if more energy is released on hydration than is stored in the ionic solid lattice. here solubility is not favoured because lattice energy is too high compared to the energy released by hydration. This high lattice energy is due to the strong ionic interaction between Ag+ and Cl- hence the answer is option C.

4. The main factors effecting the solubility of a compound in water are (1) polarity of molecule and (2) tendency to form hydrogen bond with water.. more polarity and more tendency to form hydrogen bond will increase the solubility. here ammonia is polar and have ability to form hydrogen bond also. on the other hand in nitogen chence to get polarised is less since it is homo diatomic ie both the atom are same hence there is only little chance to get polarised due to london forces which is week. hence it will be less soluble. hence the answer is option C

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