Hardy-weinberg with two populations Each of the two isolated populations is in H

Question

Hardy-weinberg with two populations

Each of the two isolated populations is in Hardy-Weinberg equilibrium (HWE) and the number of individuals in different genotype categories in the two populations is shown below:
Genotype         AA Aa aa
Population 1    4     32    64
Population 2 64    32    4
A. If the populations join together to form a single population, calculate the allele and genotype frequencies in the population immediately after merger.
B. Use the chi-square test to determine if the merged population is in HWE.
C. In class we found that a population of 50 Aa and 50 aa individuals is not in HWE. Would the population be in HWE after one generation of random mating?

Please explain how you got your answers

Explanation / Answer

population 1 :

AA = 4, then p =( 2 x 4 + 32) /200= 0.2

Aa = 32

aa= 64, then q = (2 x 64 +32)/200 = 0.8

Total = 100

population 2:

AA= 64 , then p = (2 x 64 + 32 )/200 =0.8

Aa= 32

aa= 4, then q = ( 2 x 4 + 32) / 200= 0.2

Total =100

A. If the populations join together to form a single population, calculate the allele and genotype frequencies in the population immediately after merger.

Frequency after merging a = 0.5 and A = 0.5

AA = (0.2/0.8 = 0.25)

AA = 0.25 , Aa = 0.5 and aa = 0.25

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