Texas State University-CHEM 1341-Spring18- PATTERSON (Sec. 2 Learning iversity-C

Question

Texas State University-CHEM 1341-Spring18- PATTERSON (Sec. 2 Learning iversity-CHEM 1341-Spring18-PATTERSON (Sec.257,259, and 262) Activities and Due Dates Chapter 4 Homework 3/1/2018 08:00 AM 0 69.6/100 Print i CalculatorPeriodic Table Question 26 of 33 General Chemistry 4th Edition University Science Books presered by Saping Learming How many milliliters of 10.0 M HCl(aq) are needed to prepare 250.0 mL of 1.00 M HCI(aq)? Number Previous& Give Up & View Solution Check AnsworNextExit erms of

Explanation / Answer

number moles of HCl = molarity * volume of solution in L

number of moles of HCl = 1.00 * 0.250 = 0.250 mol

Moalrity = number of moles / volume of solution in L

10.0 = 0.250 mol / volume of solution in L

volume of solution in L = 0.250 / 10.0 = 0.0250 L

1L = 1000 mL

0.0250 L = 25.0 mL

Therefore, the volume of solution = 25.0 mL

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