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Search Textbook Solutix s write the example pro X·Alabama State Unvers X Search Textbook Solut x eChemistry question Southwest Arines Sex x- d www.saplinglearning.com/ibiscms/mod/ibis/view.php?id=4589194 New Tab Sapling Learning macmilan learming ::: Apps Scholarship Award Scholarship Opportu "Hit the Books. Scho Print @Calculator-. Periodic Table Question 19 of 20 Due Date: Points Possible: Grade Category: 2/26/2018 11:59 PM 100 Quiz 3 Sapling Learning For the diprotic weak acid H2A, Ka 3.010 and K 7.0 10 What is the pH of a 0.0650 M solution of H A? What are the equilibrium concentrations of H2A and A this solution? in Policies: 10 You can check your answers You can view solutions after the due date. You have three attempts per question. There is no penalty for incorrect answers. eTextbook pH- 12 0 Help With This Topic 15 OWeb Help & Videos 16 0 17 OTechnical Support and Bug Reports 19 0 Previous 9 Check AnswerNext Exit Hint 20 9:30 PM O Type here to search ^2/25/2018

Explanation / Answer

concentration of H2A solution = 0.0650 M

H2A ------------------ HA- + H+

0.0650                 0        0

-x                       +x        +x

0.0650 -x           +x        +x

Ka1= [HA-][H+]/{H2A]

3.0x10^-5 = x*x/(0.0650-x)

for solving the equation

x= 0.00138

[H2A] = 0.0650 - 0.00138 = 0.0636M

so [HA-] = 0.00138M

[H+]= 0.00138M

-log[H+] = - log(0.00138)

PH= 2.86

PH of the solution= 2.86

          HA- ------------------- H+ + A-2

0.00138                      0.00138  

Ka2= [H+] [A-2]/[HA-]

7.0x10^-9 = 0.00138 x[A-2]/0.00138

[A-2]= 7.0x10^-9 M

for poly protic acid Ka1 value is used to calculating the PH of the solution.

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