Even obtained the following absorbance data: Concentration (nM) absorbance 13.0
ID: 710778 • Letter: E
Question
Even obtained the following absorbance data:
Concentration (nM)
absorbance
13.0
.095
16.2
.143
19.4
.205
22.6
.241
25.8
.312
A graph of this data revealed the line equation Is y=.0166x-.1223 with an R^2 square value of .99234
a. a. Evan measures an unknown solution with an absorbance of .448. What is the concentration of the solution?
b. b. Evan takes 1.0 ml of a solution and dilutes it to 50.0ml. The absorbance is .192. What is the concentration of the original solution?
plplease show work!!!!
Concentration (nM)
absorbance
13.0
.095
16.2
.143
19.4
.205
22.6
.241
25.8
.312
Explanation / Answer
a) given y= 0.448 , therfore from y=.0166x-.1223, x= 34.355 nM
b) again, y=0.192 , therfore x=18.93M, therfore concentration of original solution = 50*18.93 = 946.5 nM
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