1. Calculate the mass of water produced when 9.11 g of butane reacts with excess
ID: 709170 • Letter: 1
Question
1. Calculate the mass of water produced when 9.11 g of butane reacts with excess oxygen. Express the mass of water numerically in grams. 2. Calculate the mass of butane needed to produce 46.9 g of carbon dioxide. Express the mass of butane numerically in grams. 3. How many moles of nitrogen, n, are in 70.0g of nitrous oxide, n2O? 4. What is the mass of 5.20 moles of magnesium chloride, MgCl2?1. Calculate the mass of water produced when 9.11 g of butane reacts with excess oxygen. Express the mass of water numerically in grams. 2. Calculate the mass of butane needed to produce 46.9 g of carbon dioxide. Express the mass of butane numerically in grams. 3. How many moles of nitrogen, n, are in 70.0g of nitrous oxide, n2O? 4. What is the mass of 5.20 moles of magnesium chloride, MgCl2?
Explanation / Answer
1) C4H10 + 6.5O2 --->4CO2 +5 H2O
so moles of butane=9.11/58
=0.157
so moles of water=5*0.157
=0.785
so mass of water=18*0.785
=14.136 grams
2)moles of CO2=46.9/44
=1.066
so moles of butane=1.066/4
=0.266
so mass=0.266*58
=15.455 grams
3)nole os N2O=70/44
=1.59
4)mass=5.2*95
=494 grams
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