1. A sample of propane, C3H8 , contains 18.0 moles of carbon atoms. How many tot

Question

1. A sample of propane, C3H8 , contains 18.0 moles of carbon atoms. How many total moles of atoms does the sample contain? Express the total number of moles of carbon and hydrogen numerically. 2. Calculate the number of moles of magnesium, chlorine, and oxygen atoms in 6.40 MOLES of magnesium perchlorate, . MG(ClO4)2 Express the number of moles of MG, CL, and O atoms numerically, separated by commas. 3. What is the mass of 5.20 MOLES of magnesium chloride, MGCL2? Express your answer numerically in grams. 4. How many moles of nitrogen, N, are in 70.0 Gof nitrous oxide, N2O? Express your answer numerically in moles. 5. Calculate the mass of water produced when 9.11 G of butane reacts with excess oxygen. Express the mass of water numerically in grams. 6. Calculate the mass of butane needed to produce 46.9 G of carbon dioxide. Express the mass of butane numerically in grams.

Explanation / Answer

1) There are 3 moles of carbon atoms per molecule of propane, so there are 6 moles of propane. And there are (6x8) = 48 moles of hydrogen atoms. 2) Magnesium perchlorate Mg(ClO4)2 will have 1 x 6.40 moles of Mg = 6.40 moles, 2 x 6.40 = 12.8 moles of Cl, and 8 x 6.40 = 51.2 moles of Oxygen atoms. 3) (5.2 x 24.305) + (5.2 x 2 x 35.453) = 495.10 g 4) N2O = 44.013 g/mol 70/44.013 = 1.59 moles. N = 1.59*2 = 3.18 moles (or half that for the diatomic N2). 5) C4H10 + xs O2 = 5 H2O + other stuff. Butane MW = 58.12 g/mol... 9.11/58.12 = 0.1567 moles * 5 = 0.784 moles water. Water MW = 18.0153 g/mole *0.784 = 14.12 g 6) C4H10 + xsO2 ---> 4CO2 + other stuff. MW CO2 = 44.01 g/mole.... 46.9g/44.01 = 1.066 moles. 1.066/4 = 0.266 moles of butane. 0.266 moles * 58.12 (MW butane) = 15.48 g of butane

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