Zinc metal reacts with hydrochloric acid according to the following balanced equ

Question

Zinc metal reacts with hydrochloric acid according to the following balanced equation. <?xml:namespace prefix = o ns = "urn:schemas-microsoft-com:office:office" />

Zn+2HCl<?xml:namespace prefix = v ns = "urn:schemas-microsoft-com:vml" /> ZnCl2+H2

When 0.107 g of Zn is combined with enough HCl to make 50.7mL of solution in a coffee-cup calorimeter, all of the zinc reacts, raising the temperature of the solution from 21.8 degre celcius to 24.0degre celcius.

Find delta Hrxn for this reaction as written. (Use 1.0 g/mL for the density of the solution and 4.18 J/g.degre celcius as the specific heat capacity.)

Explanation / Answer

moles of zinc=0.107/65

=1.646*10^-3 moles.so,

heat energy released=mcT

=50.7*4.18*(24-21.8)

=466.237 J

so H reaction=-466.237/(1.646*10^-3)

=-283.25 kJ/mol

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