Using the balanced reaction: 2KMno4 (aq) + 5H2O2 (aq) + 6HCl (aq) -> 2MnCl2 (aq)

Question

Using the balanced reaction:

2KMno4 (aq) + 5H2O2 (aq) + 6HCl (aq) -> 2MnCl2 (aq) + 5O2 (g) + 8H2O (l) + 2KCl (aq)

Now I must complete the complete ionic equation (hint: MnO4- is the polyatomic ion "permanganate", and H2O2 "hydrogen peroxide" is not an acid) and then the net ionic equation.

So far for the complete ionic equation I have:

2K+ (aq) + 2MnO4- (aq) + 10H2+ (aq) +6H+ (aq) + 6Cl- (aq) -> 2Mn+2 (aq) + 4Cl- (aq) + 10O2 -2 (g) + 8H2O (l) + 2K+ (aq) + 2Cl- (aq)

I am just not sure if I'm doing this completely right. The coefficients and then whether I am supposed to leave the 2 by the H and the 2 by the O in the reactant side? Please help!

Explanation / Answer

2KMnO4 + 6HCl --> 2MnCl2 + 2KCl + 3H2O + 5[O] and

5H2O2 ---> 5H2O + 5[O]

So, the ionic equation should be :

2K+ (aq) + 2MnO4- (aq) + 6H+ (aq) + 6Cl- (aq) --> 2Mn+2 (aq) + 4Cl- (aq) + 5O2 (g) + 8H2O (l) + 2K+ (aq) + 2Cl- (aq)

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