determined the enthalp change for the decomposition of calcium carbonate CaCO3--

Question

determined the enthalp change for the decomposition of calcium carbonate CaCO3----->CaO+CO2 given the thermal equations below.

Ca(OH)2--->CaO+H2O                                         DELTArH= 65.2 kJ/mol-rxn

Ca(OH)2+CO2--->CaCO3+H2O                                          = -113.8

C+O2--->CO2                                                                      = -393.5

2Ca+O2--->2CaO                                                                =-1270.2

ALSO: Determine delta r H for the following

2NH3+5/2 O2---> 2NO+3H2O GIVEN THE THERMOCHEMICAL EQUATIONS BELOW

N2+O2-->2NO                  DELTArH= 180.8kJ/mol-rxn

N2+3H2-->2NH3                              =-91.8

2H2+O2-->2H2O                              = -483.6

BE SPECIFIC FOR BOTH

Explanation / Answer

1st equation

delta H = for reaction = 113.8-393.5-35.2-1270.2 = -1585.1

2nd equation

delta H for reaction = 91.8+180.8-(1.5*483.6) = -452.8

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