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y Bookmarks People Window Help × ( Cengage xy ? owLv2] Online teaching and X ngagenow con irtakeAssignment take valentActivity.do?lo atrassignment-take&takeAssignm.;:. ? E Use the References to access important values If needed for this question. An aqueous solution contains 0.421 M hypochlorous acid. Calculate the pH of the solution after the addition of 3.29 102 moles of sodium hydroxide to 15S mL of this solution. (Assume that the volume does not change upon adding sodium hydroxide) pH Submlt Answer Retry Entire Group 9 more group attempts remaining Previous Next Save and E

Explanation / Answer

no of moles of hypochlorous acid ( HClO) = molarity * volume in L

                                                                    = 0.421*0.155    = 0.065255moles

no of moles of NaOH    = 3.29*10^-2 moles   = 0.0329 moles

                 HClO(aq) + NaOH(aq) ----------> NaClO(aq) + H2O(l)

I                0.065255    0.0329                       0

C              -0.0329       -0.0329                       0.0329

E              0.032355         0                             0.0329

              Pka of HClO   = 7.54

PH    = PKa + log[NaClO]/[HClO]

         = 7.54 + log0.0329/0.032355

         = 7.54 + 0.007254   = 7.5473 >>>>answer

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