Please Show Formula and Steps - I need to know how to complete on my own Acetyle

Question

Please Show Formula and Steps - I need to know how to complete on my own

Acetylene gas, C2H2(g), is used in welding.

Part A

Part complete

Write a balanced equation for the combustion of acetylene gas to CO2(g) and H2O(l).

Express your answer as a chemical equation. Identify all of the phases in your answer.

2C2H2(g)+5O2(g)?4CO2(g)+2H2O(l)

SubmitPrevious Answers

Correct

Part B

How much heat is produced in burning 6 mol of C2H2 under standard conditions if both reactants and products are brought to 298 K?

Express your answer using five significant figures.

nothing

SubmitPrevious AnswersRequest Answer

Incorrect; Try Again; 4 attempts remaining

Part C

What is the maximum amount of useful work that can be accomplished under standard conditions by this reaction when 6 mol of C2H2 is burned?

Express your answer using five significant figures.

nothing

SubmitRequest Answer

2C2H2(g)+5O2(g)?4CO2(g)+2H2O(l)

Explanation / Answer

part B

2C2H2(g)+5O2(g) -----> 4CO2(g)+2H2O(l)

DHrxn = (4*DH0f,CO2(g)+2*DH0f,H2O(l))-(2*DH0f,C2H2(g)+5*DH0f,O2(g))

      = (4*-393.5+2*-285.8)-(2*226.7+5*0)

      = -2599 kj

2 mol C2H2 = -2599 KJ

6 mol C2H2 = -2599*6/2 = -7797 Kj

ANSWER: 7.7970*10^3 kj

PART c

dGrxn = (4*DG0f,CO2(g)+2*DG0f,H2O(l))-(2*DG0f,C2H2(g)+5*DG0f,O2(g))

      = (4*-394.4+2*-237.1)-(2*209.2+5*0)

      = -2470.2 kj

dGrxn = Wmax

Wmax per 2 molC2H2 = -2470.2 kj

   6 mol C2H2 = -2470.2*6/2 = -7410.6 kj
   

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.