Stoichiometry Part I: Percent Yield Purpose: To make NaC1 from NaHCO, and HCL an

Question

Stoichiometry Part I: Percent Yield Purpose: To make NaC1 from NaHCO, and HCL and to determine the percent yield of the reaction Prelab (Part I): (see next page for prelab part II . Prepare lab notebook to receive data 2. Determine the molar mass of NaHCO. 3. What are the systematic names of the 2 reactants? 4. Convert 3.00 g NallCO, to moles. Procedure 1. Weigh 250 mL beaker 2. Weigh 3.00g NaHCO, into beaker. 3. In the hood, add concentrated HCl drop wise until fizzing stops. 4. Dry the contents of the beaker by placing the beaker on a hotplate (also in the hood). The hotplate should not be set above the max heat. (While this is dying continue on to Part 11 of the lab.) 5. Once beaker is cooled, weigh beaker to determine actual yield of NaCl 6. Calculate theoretical yield for Naci (g NaHCO-mol Nalico, mol Naci-g NaCl) 7. Determine percent yield. Actual Yield %Yield- ??? x 100 ?.? Theoretical Yield Calculate Theoretical Yield: (g Nalico) ? (mol NaHCO)-. (mol Naci)-(g No 49

Explanation / Answer

prelab (part-1):

1.note book is ready.

2. Molar mass of NaHCO3 ?

Answer: atomic mass of Na-23, H-1, C-12, 0-16,

then molar mass of NaHCO3= Na*1+H*1+C*1+O*3

=23*1+1*1+12*1+16*3

=84

3. sodium bicarbonate, sodium chloride.

4.3g of NaHCO3 into moles,?

moles formula = weight/molecular weight

=3/84

=0.0357

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