Pb2+ + 2e- -> Pb(s) ?=-0.13V Ag+ + 1e- -> Ag(s) ?=+0.80V Pb(s)| Pb 2+ (1M) || Ag

ID: 706327 • Letter: P

Question

Pb2+ + 2e- -> Pb(s) ?=-0.13V
Ag+ + 1e- -> Ag(s) ?=+0.80V

Pb(s)| Pb2+ (1M) || Ag+ (1M) | Ag(s)

Determine which of the following statements about the cell shown are True or False.

As the reaction proceeds, the concentration of the silver ions increases.

The lead half-cell is the cathode.

The silver electrode is the anode.

The mass of the lead electrode is increasing.

Cations move to the silver half-cell.

The cell, as represented by the line notation, is an electrolytic cell.

Electrons are spontaneously produced in the lead half-cell.

The standard cell potential, ?o, equals 0.93 V.

FRO THE REDUCTIONPOTENTIAL VALUES , SINCE Pb IS HAVING -ve REDUCTIONPOTENTIAL VALUE IT IS ANODE AND SILVER WITH + ve POTENTIAL VALUE IT IS CATHODE.

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As the reaction proceeds, the concentration of the silver ions increases.-------------FALSE

SILVER METAL(NOT ION) INCREASES, CONCENTRATION OF LEAD ION INCREASES.

The lead half-cell is the cathode.- ------------------------------------- FALSE

LEAD HAFL CELL IS ANODE

The silver electrode is the anode.----------------------- FALSE

SILVER ELECTRODE IS CATHODE.

The mass of the lead electrode is increasing.---------------- FALSE

mass OF SILVER INCREASES.

Cations move to the silver half-cell.----------------- FALSE

ELECTRONS OVE TO SILVER HALF ELECTRODE.

The cell, as represented by the line notation, is an electrolytic cell.--------------------------FALSE

IT IS ELECTROCHEMICAL CELL

VOLTAGE IS PRODUCED BY REDOX REACTION

Electrons are spontaneously produced in the lead half-cell.----------------- TRUE

LEAD IS OXIDISED

The standard cell potential, ?o, equals 0.93 V.-------------------------TRUE

Ecell = E cathode-Eanode

= 0.80-(-0.13) = 0.93V

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