We were given a worksheet in class to finish up and this is the question regardi

Question

We were given a worksheet in class to finish up and this is the question regarding Infrared Spectroscopy. Its a very long question but I just broke it up into the main portions of the question.

C) Infrared Spectroscopy

1) What is it and why do we use it?

2) IR Chart: Note landmark absorptions (O-H, C-H, C=O, C=C, C-O, etc). Where do these occur?

3) IR spectra of 2-hexanol and 2-hexanone- compare the peaks present and absent in each spectrum

4) Examine the IR spectra of Camphor and Isoborneol. While they are similar, they also have differences. What are those differences?

Explanation / Answer

IR spectroscopy is a technique used for the determination of functional groups in compounds. It utilizes infrared radiation, that interacts with matter measuring the absorption of radiation as a function of frequency or wavelength.

O-H stretching occurs at around 3500 cm-1

C-H stretching occurs at around 3000 cm-1

C=O stretching occurs at around 1700 cm-1

C=C stretching occurs at around 1600 cm-1

C-O stretching occurs at around 1050-1150 cm-1

2-hexanol shows a broad peak around 3500 cm-1 for O-H stretching which is absent in 2-hexanone, where the major peak is around 1700 cm-1 for C=O stretching. C-H peak at around 3000 cm-1 are obtained for both.

Isoborneol is obtained on reduction of camphor. The IR spectrum of camphor shows peaks at 3000 cm-1 (C-H stretching), 1700 cm-1 (C=O stretching). While isoborneol also shows peak at around 3000 cm-1 for C-H stretching, the narrow peak at 1700 cm-1 is absent and instead a broad peak is obtained at 3500 cm-1 for O-H stretching.

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