The ionization energy of an atom can be measured by photoelectron spectroscopy,

Question

The ionization energy of an atom can be measured by photoelectron spectroscopy, in which light of known wavelength is directed at an atom, causing an electron to be ejected. The kinetic energy of the ejected electron is measured by determining its velocity and using the equation for kinetic energy. The ionization energy can then be calculated using the relationship that the energy of the incident light is equal to the sum of the ionization energy and kinetic energy The energy of a photon of wavelength 58.4 nm is kJ (3 s.f). The velocity of the electron ejected by this photon is 2.450X100 m/s. The energy of a mole of these photons is kJ/mole. The energy of an ejected kJ. The energy of a electron is mole of these electrons is kJ/mole. The ionization energy is kJ/mole. (Use E to express powers of 10, e.g 6.02x1023 entered as 6.02E23.)

Explanation / Answer

1) energy of a photon=3.4E-15

2)energy of a ejected electron= 2.7E-18

3)ionisation energy=3.3973E-15

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.