270, mm Hg? M-mous = A) 0.0565 moVL B) 0.355 moVL C) 0448 moVL D) 42.9 mol/L 24)
ID: 705761 • Letter: 2
Question
270, mm Hg? M-mous = A) 0.0565 moVL B) 0.355 moVL C) 0448 moVL D) 42.9 mol/L 24) Determine the freezing point of a solution that contains 78.8 g of naphthalene (C1oHs. molar mass- 128.16 g/mol) dissolved in 722 ml of benzene (d- 0.877 g/mL). Pure benzene has a melting point of S.S0°C and a freezing point depression constant of 490°Cm A) 4.76 C B) 4.17°C C) 0.74°C D) 1.33 C E) 1.68 C 25) Calculate the frecezing point of a solution of 500.0 g of ethylene glycol (C2H602) dissolved in 5000 g of water. Kf-1.86C/m and Kb- 0.512 C/m. A)30.0? B) -30.0°C C) 8.32 C D) -8.32°C E)70.2°C 8.06: 16.12 =2496 -505 X 26) Calculate the boiling point of a solution of 500.0 g of ethylene glycol (C2H602) dissolved in 500.0 g of water. Kf- 1.86°C/m and Kb-0.512 C/m. Use 100°C as the boiling point of water. A) 1080 B) 92 C C) 130°C D) 70? E) 8.3°C E) 1.90 g 11) Calculate the molality of a solution that is prepared by mixing 25.5 ml. of ld·0.792 ginl) and 387 mL ofCH3CH2CH2OH(d,0.811-pmLy A) 0630m m B) 0.812 m C) 1.57 m D) 2.01 m E) 4.98 m IDf A solution is prepared by dissolving 58.6 g sucrose (C12H2201) in 495 g of water. Determine the mole fraction of sucrose if the final volume of the solution is 508 mL 4.09 × 10-3 B) 7.80 x 10-2 C) 1.28 x 10-3 D) 7.23 x 10-2 E) 245 x 10-3 342 13) A solution is ume A) 6 B) 1.65 x 10-2 C) 1.40 x 10-3 D) 1.32 x 10-2 E) 8.84 x 10-2 05Imols 05I t 510 mlHo M0,Explanation / Answer
I am solving the first question in the sheet as per Chegg guidelines, post multiple question to get the remaining answers
Q24)
Molality = Number of moles of solute/mass of solvent in Kg
Number of moles of solute (napthalene) = mass/molar mass = 78.8/128.16 = 0.6148 moles
mass of solvent = volume of solvent * density of solvent = 722 mL * 0.877 g/mL = 633.19g = 0.633 kg
molality = 0.6148/0.633 = 0.9712m
Depression in freezing point = i * Kf * m = 1 * 4.90 * 0.9712 = 4.76
New Freezing point = old freezing point - depression = 5.50 - 4.76 = 0.74C
Correct answer is Option C
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