. Place this neotner eha ol the bond attached to the O atom. H atom on the free
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Question
. Place this neotner eha ol the bond attached to the O atom. H atom on the free bond of the O creates a 5-membered ring. O atom at C#4 to Cal . This atom at C#1 (this is the bond that you disconnected from the C of the C-o.) HOH H-F-OH ??? CH20H CH OH c. Draw your cyclic model by adding the OH groups and H atoms to the figure below. Make certain that your model is oriented with the O at the back and the HOCH2on the top. There are two correct answers for the orientation of the-OH group at C# 1, depending on which C-O bond you pulled apart in step #1 directly above. ott 64 et 9, why is there no OH group on C#4 of the cyclic sugar? a) A molecule of H,O is lost in a dehydration reaction. b) The molecule undergoes oxidation. c The molecule undergoes reduction. d) The OH group is used to make the ring. Pick the best answer 10. Is the compound below an enantiomer or a diastereomer of your cyelic sugar? and explanation below. HoCH ?? a) A diastereomer because the orientation of all of the chiral C atoms is reversed. b) A diastereomer because the orientation of just some of the chiral C atoms is reversed. c) An enantiomer because the orientation of all of the chiral C atoms is reversed. d) An enantiomer because the orientation of just some of the chiral C atoms is reversed.Explanation / Answer
Q10 The correct answer is (B) A diastereomer because the orientation of just some of the chiral C atoms is reversed
Diastereomers are stereoisomers which differ from one another in structure because one or more chiral centers have different geometry when compared one stereoisomer to another.
Here the compound given in question 10 differs from original cyclic sugar only at carbon atom marked number 3 where as the stereochemistry (or orientation) of all other carbon atoms (except #3) is same. Hence the compounds are diastereomerss
For two molecules to be enantiomers, they must be mirror images of each other which means stereochemistry at every chiral center will change, which is not the case here,
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