Answer the questions on acids, bases, pH and buffers. Questions and Problems Q1
ID: 704574 • Letter: A
Question
Answer the questions on acids, bases, pH and buffers.Questions and Problems Q1 Complete the following table: H,0*1 TOH pH Acidic, Basic, or Neutral'? 2.0x10-6 9.8 3.5x10-3 O2 A solution has a [OH-]-4.0x10-5 M. What are the [H3O+] and the pH of the solution? A sample of 0.0084 mol of HCl is dissolved in water to make a 1500-mL solution. Calculate the molarity of the HCl solution, the [H30*1, and the pH. For a strong acid such as HCl, the [H30 is the same as the molarity of the HCI solution Q3 HCI(aq) + H2O(l)- -H,0+ (aq) + ?? (aq)
Explanation / Answer
Ans 1
Part a
[H3O+] = 2.0 x 10^-6
pH = - log [H3O+]
= - log (2.0 x 10^-6)
= 5.7 < 7 (acidic)
pOH = 14 - pH = 14 - 5.7 = 8.3
[OH-] = 10^-pOH = 10^(-8.3) = 5.01 x 10^-9
Part b
pH = 9.8 > 7 (basic)
pOH = 14 - 9.8 = 4.2
pH = - log [H3O+]
[H3O+] = 10^-pH = 10^(-9.8) = 1.58 x 10^-10
[OH-] = 10^-pOH = 10^(-4.2) = 6.31 x 10^-5
Part c
[OH-] = 3.5 x 10^-3
pOH = - log [OH-] = - log (3.5 x 10^-3) = 2.5
pH = 14 - pOH = 14 - 2.5 = 11.5 > 7 (basic)
[H3O+] = 10^-pH = 10^(-11.5) = 3.16 x 10^-12
Part d
Neutral
pH = 7
pOH = 14 - 7 = 7
[H3O+] = 10^-pH = 10^(-7) = 1.0 x 10^-7
[OH-] = 10^-pOH = 10^(-7) = 1.0 x 10^-7
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