Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Answer the questions on acids, bases, pH and buffers. Questions and Problems Q1

ID: 704574 • Letter: A

Question

Answer the questions on acids, bases, pH and buffers.
Questions and Problems Q1 Complete the following table: H,0*1 TOH pH Acidic, Basic, or Neutral'? 2.0x10-6 9.8 3.5x10-3 O2 A solution has a [OH-]-4.0x10-5 M. What are the [H3O+] and the pH of the solution? A sample of 0.0084 mol of HCl is dissolved in water to make a 1500-mL solution. Calculate the molarity of the HCl solution, the [H30*1, and the pH. For a strong acid such as HCl, the [H30 is the same as the molarity of the HCI solution Q3 HCI(aq) + H2O(l)- -H,0+ (aq) + ?? (aq)

Explanation / Answer

Ans 1

Part a

[H3O+] = 2.0 x 10^-6

pH = - log [H3O+]

= - log (2.0 x 10^-6)

= 5.7 < 7 (acidic)

pOH = 14 - pH = 14 - 5.7 = 8.3

[OH-] = 10^-pOH = 10^(-8.3) = 5.01 x 10^-9

Part b

pH = 9.8 > 7 (basic)

pOH = 14 - 9.8 = 4.2

pH = - log [H3O+]

[H3O+] = 10^-pH = 10^(-9.8) = 1.58 x 10^-10

[OH-] = 10^-pOH = 10^(-4.2) = 6.31 x 10^-5

Part c

[OH-] = 3.5 x 10^-3

pOH = - log [OH-] = - log (3.5 x 10^-3) = 2.5

pH = 14 - pOH = 14 - 2.5 = 11.5 > 7 (basic)

[H3O+] = 10^-pH = 10^(-11.5) = 3.16 x 10^-12

Part d

Neutral

pH = 7

pOH = 14 - 7 = 7

[H3O+] = 10^-pH = 10^(-7) = 1.0 x 10^-7

[OH-] = 10^-pOH = 10^(-7) = 1.0 x 10^-7

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote