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(5) Lab& Percent hydration Balance Chemical Equation + v edu vebapps/asessment/t

ID: 704005 • Letter: #

Question

(5) Lab& Percent hydration Balance Chemical Equation + v edu vebapps/asessment/tace/läunchjsp course assessment.de 208209 1course id 20925 ontent id 1781616 1 51 55 QUESTION 2 10 po Similar to the Experimental Percent Hydration, one can find the Theoretical Percent Hydration of a compound using reference values The mass of each atom is found on the periodic table, and represents the average mass of all the lsotopes that exist for that element For example, the mass of carbon on the perioidic table is 12 01 This represents an average of carbon isotopes such as Carbon 12 Carbon 14, and more The masses of each atom are then added together to create the mass off the whole compound. The masses of hydrated magnesium sulfate, and water are used in your calculations of percent hydration Find the Theoretical Percent Hydration of magnesium sulfate hydrate, Mg SO 7HgO. To do this, you will need the mass of the hydrate MgS04 7H20), and the mass of the water in the hydrate (7 times the mass of water) You will then set up a fraction showing the mass of water over the mass of the hydrated sample. This represents t compound made by water Muiiply by 100 to get a percent the fraction of the Use the equation in your lab to find Theoretical Percent Hydration of your sample, using the mass values found on your periodic table, to the nearest 2 decimal places Use the proper rules for significant Sgures to select the correct answer below Note you will want a separate piece ot paper to do thial This is not meant to be done in your hoad 51 17 51 168 ? 0.51167 ? 0.51 168 Cek Save and Subonit to save and ubmit Click Save All Answers to sove all as Save All Answers ouo

Explanation / Answer

Molecular mass of Mg = 24.305

Molecular mass of S = 32.065

Molecular mass of O = 15.9994

Molecular mass of H = 1.00794

Molecular mass of MgSO4 = 24.305 + 32.065 + 4*15.9994

= 120.3676

Molecular mass of 7H2O = 14*1.00794 + 7*15.9994

= 126.10696

Molecular mass of MgSO4-7H2O = 120.3676 + 126.10696

= 246.47456

Theoretical % hydrate

= Molecular mass of 7H2O x 100 / Molecular mass of MgSO4-7H2O

= 126.10696 x 100 / 246.47456

= 51.17 %

Option A is the correct answer