History Bookmarks People Window Help mmunity Co x login microsoftonline.com xWil

Question

History Bookmarks People Window Help mmunity Co x login microsoftonline.com xWileyPLUS /edugen.wileyplus.com/edugen/lti/main.uni Return to Blackboard Hein, Foundations of College Chemistry, 15e Hele I Paired Exercise 15.23 Determine the molar concentration of each ion present in the solutions that result from each of the following mixtur (Disregard the concentration of H and OH from water and assume that volumes are additive.) (a) 55.4 mL of 0.37 M HCI and 82.2 mL of 1.84 M HC (b) 147 mL of 0.53 M CaCl2 and 147 mL of 0.26 M Caci2 M Ca2+ M CI (c) 32.8 mL of 0.383 M NaOH and 23.1 mL of 0.276 M HCI M Na ?.. ?? @j

Explanation / Answer

Part a

Moles of HCl = molarity x volume

= 0.37 mol/L x 55.4 mL x 1L/1000 mL

= 0.020498 mol

Moles of HCl = molarity x volume

= 1.84 mol/L x 82.2 mL x 1L/1000 mL

= 0.151248 mol

Total Moles of HCl = 0.151248 + 0.020498 = 0.171746 mol

Total volume = 55.4 + 82.2 = 137.6 mL x 1L/1000 mL

= 0.1376 L

HCl = H+ + Cl-

[H+] = 0.171746 mol / 0.1376 L = 1.248 M

[Cl-] = 1.248 M

Part b

Moles of CaCl2 = molarity x volume

= 0.53 mol/L x 147 mL x 1L/1000 mL

= 0.07791 mol

CaCl2 = Ca2+ + 2Cl-

Moles of Ca2+ = 0.07791

Moles of Cl- = 2*0.07791 = 0.15582

Moles of CaCl2 = molarity x volume

= 0.26 mol/L x 147 mL x 1L/1000 mL

= 0.03822 mol

Moles of Ca2+ = 0.03822

Moles of Cl- = 2*0.03822 = 0.07644

Total Moles of Ca2+ = 0.03822 + 0.07791 = 0.11613

Total volume = 147 + 147 = 294 mL = 0.294 L

[Ca2+] = 0.11613 / 0.294 = 0.395 M

Total Moles of Cl- = 0.07644 + 0.15582 = 0.23226 mol

[Cl-] = 0.23226 mol / 0.294 L

= 0.790 M

Part c

Moles of NaOH = molarity x volume

= 0.383 mol/L x 32.8 mL x 1L/1000 mL

= 0.0125624 mol

Moles of HCl = 0.276 mol/L x 23.1 mL x 1L/1000 mL

= 0.0063756 mol

NaOH + HCl = NaCl + H2O

Moles of NaOH remain = 0.0125624 - 0.0063756

= 0.0061868 mol

Moles of Na+ = 0.0061868 mol

Total volume = 32.8 + 23.1 = 55.9 mL = 0.0559 L

[Na+] = 0.0061868 mol / 0.0559 L

= 0.111 M

Related Questions

Navigate

• Browse (All)
• Browse H
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.