9 Liquid propane (used in things like gas grils) combusts acording to the follow

Question

9 Liquid propane (used in things like gas grils) combusts acording to the following equation: What volume of carbon dioxide gas, in L, will be produced from the combustion of 72 propane (C&He;) at 700 C and 1.005 atm? 0 grams of 10. Cumulative problem. Consider the following balanced chemical reaction. How many liters of bromine gas (Bra) at 300 C and 735 torr are formed when 275 g of sodium bromide reacts with 176 g of sodium bromate (NaBrO)? (Hint! Find your limiting reactant... 5 NaBr(aq)+ NaBrO,(aq)+3 H,So(aq)3 Bralg)+3 Na,Sos(aq)+3 HOU)

Explanation / Answer

Ans 9

Moles of propane = mass/molecular weight

= 72g / 44.1g/mol

= 1.6326 mol

From the stoichiometry of the reaction

1 mol propane produces = 3 mol CO2

1.6326 mol propane produces = 3 x 1.6326 = 4.897 mol CO2

From the ideal gas equation

PV = nRT

V = 4.897 mol x 0.0821 L-atm/mol-K x (700+273)K / 1.005 atm

V = 389.32 L

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