RADIATION SAFETY MATH PROBLEMS You are in a radiation area that measures 60MR/HR

Question

RADIATION SAFETY MATH PROBLEMS You are in a radiation area that measures 60MR/HR. Hou much radiation will you receive if you are present for 30 seconds? How much radiation will you receive if you are 20 ft. fron a 100 curie IR 192 source for 30 seconds? What is the activity of a COBALT-60 source if the dose . rate is 300MR/HR. at a distance of 40 feet? If the dose rate of a source is 60 MR/HR. at 40 feet, at what distance will the dose rate be 120MR/HR? 36 -teeT What is the total amount of radiation that you will receive if you are 50 feet from a 50 curie IR 192 source for 5 minutes, and 40 feet from a one curie COBALT-60 curie source for 30 seconds?co A concrete wall with a thickness of 2HVL is 40 feet from a 40 curie COBALT-60 source. You are on the other side, 20 feet from the wall. If you are present there for 3 minutes, how much radiation would you receive? (Assume that you are 60 feet from the source). At what distance from a 20 curie (unshielded) IR 192 source would the dose rate be 2MR/HR? ow long could you be a 10 feet from a 50 curie IR 192 source and receive a maximum of 200 MR? If you picked up 40MR at 20 feet from a source for a given amount of time, how much radiation would you pick up at 100 feet for the same amount of time? How many exposures could you make with a 50 curie source if each exposure is 30 minutes long, you are 20 eet from the source, and you can not pick up more than 18MR? You have a 100 curie IR 192 source, unshielded, what would

Explanation / Answer

Ans 1

Radiation amount in the area = 60 mR/hr

mR = milliroentgen = Amount of radiation produced by Gamma or X-Ray in a cm3 of air.

hr = hour

Time = 30 s

Radiation received = 60 mR/hr x 30s x 1hr/3600s

= 0.5 mR

Ans 2

standard dose rate Ir-192 = 5.9 R/hr/Ci at 1 foot

dose rate for a 100 Ci Ir-192

= 5.9 R/hr/Ci at 1 foot x 100 Ci

= 590 R/hr at 1 foot

From the Inverse Square Rule

Initial radiation I1 = 590 R/hr

Distance D1 = 1 ft

I2 =?

D2 = 20 ft

I2 = I1 x (D1/D2)2

= 590 R/hr x (1/20)2

= 1.475 R/hr

Radiation received for 30 s

= 1.475 R/hr x 30s x 1hr/3600s

= 0.01229 R x 1000mR/R

= 12.29 R

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