Lab Sec Name Dr o-2 Desk No. A. Precipitation of CaC,0H,O from the Salt Mixture

Question

Lab Sec Name Dr o-2 Desk No. A. Precipitation of CaC,0H,O from the Salt Mixture Unknown number I. Mass of beaker (g) 2. Trial I Trial 2 751y Mass of beaker and salt mixture (g) 3. Mass of salt mixture (g) 4. ?.SG72 Mass of filter paper (g) 5. Mass of filter paper and product after air-dried 3.5770 or oven-dried (g) 6.) Mass of dried product (g) 7. Formula of dried product B. Determination of Limiting Reactant 1. Limiting reactant in salt mixture (write complete formula) 2. Excess reactant in salt mixture (write complete formula) Data Analysis 1Moles of CaC,OpH,O (or CaC2O) precipitated (mol) 2. Moles of limiting reactant in salt mixture (mol) . formula of limiting hydrate- ? Mass of limiting reactant in salt mixture (g) Mass of excess reactant in salt mixture (g) 4. formula of excess hydrate . 5. Percent limiting reactant in salt mixture (%) Percent excess reactant in salt mixture (%) 7. Mass of excess reactant that reacted (8) 8. Mass of excess reactant, unreacted (g) 6. Show calculations for Trial 1 on next page. ?(a mes,of : 2.5 28

Explanation / Answer

Mass of salt mixture = 167.6514 - 166.6464 = 1.005 g

Mass of dried product = 3.5376 - 0.5672 = 2.9704 g

Moles of CaC2O4 = mass/molecular weight

= 2.9704 g / 128 g/mol

= 0.0232 mol

Moles of limiting reactant = Moles of CaC2O4 formed

= 0.0232 mol

Mass of K2C2O4 = 0.0232 mol x 166 g/mol

= 3.85 g

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