Percent (m/v) HC2H,02 in vinegar show calculation for Trial 1) Lab 10-Questions

Question

Percent (m/v) HC2H,02 in vinegar show calculation for Trial 1) Lab 10-Questions 1. A solution has a OH' concentration of i ?0" M, what are the [H] and pH of the solution? PH 2. A sample of 0.0020 mole of HCI is dissolved in water to make a 2000 mL solution. Calculate the molarity of the HCl solution, the [H'] and the pH. For a strong acid such as HCl, the [H'1 is the same molarity as the HCI solution. 3. Which of the household chemicals was most (a) acidie (b) basic (e) closest to neutrality? Page 6

Explanation / Answer

Ans 1

[OH-] = 10^-5

pOH = - log[OH-] = - log (10^-5)

= 5

pH = 14 - pOH = 14 - 5 = 9

[H+] = 10^-pH = 1 x 10^-9

Ans 2

Moles of HCl = 0.0020 mol

Volume of solution = 2000 mL x 1L/1000 mL = 2 L

Molarity of HCl = moles/Volume

= 0.0020 mol / 2L

= 0.0010 M

[H+] = 0.0010 M

pH = - log[H+] = - log (0.0010) = 3

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