anaeelest: Ouiz 2-/X(11What is SPOC diag x\'GA.what Is The Expe GE ckboard.ncat.
ID: 702331 • Letter: A
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anaeelest: Ouiz 2-/X(11What is SPOC diag x'GA.what Is The Expe GE ckboard.ncat.edu/webapps/jassessmentrake/launch jsp?course assessmentJid-,152590 18course jd- 35304 k y, Twitter e YouTube N Netflix myCampusNews Popular Birmported From Safari , imported F Remaining Time: 1 hour, 01 minute, 02 seconds Question Completion Status: QUESTION 12 6.25 If the optimistic, pessimistic, and most likely times for step 1 of a process is (2 days, 9 days, 5 days) and for step is (4 days, 13 days, 8 days), then the best estimate for the standard deviation of the total cycle for the two steps is: Oa-1.9 days O b. 2.67 days OG.3.6 days O d. 1.5 days 6.25 points QUESTION 13 f the optimistic, pessimistic, and most likely times for step 1 of a process is (2 days, 9 days, 5 days) and for step 2 is (4 days, 13 days, 8 days), then the best estimate tor the standard deviation of the total cycle tor the two steps Click šave and Submit to save and submit. Click Save All Ansavers to save all answers Save All Answers Save F7 FS F2 F3Explanation / Answer
For step 1
Pessimistic time tp = 9 days
Optimistic time to = 2 days
Variance for step 1
2 =[ (tp - to)/6]2
= (9-2/6)2 = 1.36
For step 2
Pessimistic time tp = 13 days
Optimistic time to = 4 days
Variance for step 2
2 =[ (tp - to)/6]2
= (13-4/6)2 = 2.25
Total Variance = 1.36 + 2.25 = 3.61
Standard deviation of total cycle = Variance0.5
= 3.610.5
= 1.9 days
Option A is the correct answer
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