2. A classifying hydrocyclone circuit is processing a hematite (SGoolid 5.26) an

Question

2. A classifying hydrocyclone circuit is processing a hematite (SGoolid 5.26) and water slurry, while making the separation shown below: 435 GPM slurry, 14.0% solids (by weight) Feed Slurry 86 GPM water. 72.0% solids (by weight) + Using the matrix table approach given in the Lecture Notes, prepare tables for the FEED OVERFLOW, and UNDERFLOW streams. Complete the tables for the TPH, GPM, and SG values for the solid, liquid, slurry, and solids concentrations. Indicate the given values and include all calculations and the solution order

Explanation / Answer

Feed = Slurry + Water = 86+435 = 521 GPM

Total solid in feed = Total solid in slurry + Total solid in water = .14*435+.72*86=122.82 GPM

Total water in feed = Total feed - Total solid in feed = 521-122.82=398.18

=> Solid composition in feed = 122.82/521=23.57%

SG of material = SG of solid*Solid fraction in material + SG of water*Water fraction in material

SG of water = 1

=> SG of feed = 23.57/100*5.26+(1-23.57/100)*1=2

=> SG of Slurry = 14/100*5.26+(1-14/100)*1=1.59

=>SG of water = 72/100*5.26+(1-72/100)*1=4.06

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