instructure.com/courses/131422/assignments/1596851 1. The kinematic viscosity of

Question

instructure.com/courses/131422/assignments/1596851 1. The kinematic viscosity of a hydraulic oil is 150 c.S. If the fluid is flowing in a 2-in diameter pipe at a velocity of 15 ft/s, what is the Reynold's Number of the fluid? It is laminar, within the critical zone or turbulent? 2. For laminar flow, find the head loss due to friction in units of psi for a 75ft length of pipe that 3. What is the head loss and pressure loss across a 2 in wide open globe valve when oil (SG 0.9) 4. A gear pump has a 4-in outside diameter, a 3-in inside diameter and a 1-in width. If the actual 5. A pump has a displacement volume of 15 in2. It delivers 60 gpm at 1000 rpm and 1000 psi. If the has a diameter of 2 ft. The oil has a specific gravity of 0.8 and velocity of 15 ft/s. flows through it at a rate of 25 gpm? pump flow at 2000 rpm and rated pressure is 20 gpm, what is the volumetric efficiency? prime mover input torque is 2500 in-Ib.. a. What is the mechanical efficiency? b. What is the volumetric efficiency? c. What is the overall efficiency? d. What is the theoretical torque required to operate the pumpi? A pump supplies oil at 15 gpm to a 0.5 ft diameter double acting cylinder. If the load is 800 1b (extending and retracting) and the rod diameter is 0.5 ft, find. 6. The hydraulic pressure during the extending stroke in psi The piston velocity during the extending stroke The cylinder horsepower during the extending stroke The hydraulic pressure during the extending stroke in psi The piston velocity during the extending stroke The cylinder horsepower during the extending stroke a. b. c. d. e. f.

Explanation / Answer

Ans 5

Displacement volume V = 15 in3/Rev

= 0.000245806 m3/rev

Theoretical flow rate Q = V x N

= 0.000245806 m3/rev x (1000/60)rev/s

= 0.00409676 m3/s

Actual volumetric flow rate Qa = 60 gpm = 0.0037854 m3/s

Part a

Pressure P = 1000 psi = 6.895 x 10^6 Pa

w = 2 x 3.14 x N/60

= 2*3.14*1000/60 = 104.67

Torque = 2500 in-lb = 282.462 N-m

Mechanical efficiency = Pressure x Q / Torque x w

= 6.895 x 10^6 x 0.00409676 / (282.462 x 104.67)

= 0.955 = 95.5%

Volumetric efficiency = Qa/Q

= 0.0037854/0.00409676

= 0.923

= 92.3%

Part C

Overall efficiency = mechanical x volumetric

= 0.955 x 0.923

= 0.881 = 88.1%

Part d

theoretical torque = Mechanical efficiency x actual torque

= 0.955 x 2500 in-lb

= 2387.5 in-lb

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