Please show all steps to get the answers. In Boston, due to the large amount of
ID: 701784 • Letter: P
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Please show all steps to get the answers.
In Boston, due to the large amount of snowfall during winter of 2014-2015, the city has brought in several "snow dragons" to melt the snow Model SND5400 is rated at: #180 ton rated capacity per hour (Based on Latent Heat of Ice) No. 2 Fuel Oil or Diesel Fuel Type, Jet A Fuel Propane, and Natural Gas available for stationary units Fuel storage capacity of 3,000 US gallons Burner Output at 54,000,000 btu/hr Measures 68' long x 11'6" wide x 12'4" high The USEPA states that there are 22,300 lb Co2 emitted per 1000 gal of No. 2 fuel oil burned (AP-41 Table 1.3-12). The heat content of No. 2 fuel oil is 140 MMBtu/103 gal (AP-42 Chapter 1.3). (a) How many lbs of CO2 are generated per hour when operating at maximum capacity? 8601.4 mputer's answer now shown above. Incorrect. Tries 1/6 Previous Tries (b) Calculate the lbs of CO2 are generated per ton of snow melted. 47.8 mputer's answer now shown above. Incorrect. Tries 1/6 Previous Tries (c) If the snow has a density of 24.97 b/ft3, calculate the lbs of co2 are generated per ft 3 of snow melted 5.97x10-1 Computer's answer now shown above. Tries 0/6 (d) If the snow is 79 inches deep, and the road is 30 ft in width, calculate the lbs of CO2 that are generated in clearing the snow from a length of road 2 t. 2.36x102 Computer's answer now shown above. Tries 0/6 (e) Based on the weighted average combined fuel economy of cars and light trucks in 2011, the amount of CO2 emitted per mile driven was 0.92594 lbs Co2/mile. Calculate the "equivalent miles" driven in clearing the snow from a length of road 2 ft (as in part (d) 2.55× 102Explanation / Answer
a) Burner output capacity = 54000000 btu/hr
Heat content of No. 2 fuel oil = 140 MMBTU/10^3 gal = 140*10^6/10^3 = 140000 BTU/gal
Therefore, Fuel 2 coil burning capacity = 54000000/140000 = 385.71 gal/hr
Given, 22300 lb CO2 liberated per 1000 gal Fuel 2 oil
Therefore, CO2 liberated = 22300/1000*385.71 = 8601.4 lb/hr
b) Total snow melted per hour = 180 ton/hr
CO2 liberated per ton snow generated = CO2 liberated per hour/snow melted per hour = 8601/180 = 47.8 lb/ton
c) Snow density = 24.97 lb/ft3 = 24.97 *.453*10^-3 = 0.011 ton/ft3
Therefore, snow generated per hour = 180/.011 = 16363 ft3/hr
Therefore, CO2 liberated per ft3 snow generated = 8601/16363 =0.59 lb/ft3
d) Total snow volume = depth*width*length = 79/12*30*2 =395 ft3
Therefore, total CO2 generated in melting this snow = 395*0.59 = 236 lb
e) Total CO2 generated as calculated above = 236 lb
CO2 generated/mile = .92592 lb/mile
Therefore total miles covered equivalent to CO2 produced in snow melting = 236/.92592 = 255 miles
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