1. The boiler produces saturated vapor at 285 K and 0.02MPa 2. The compressor ha
ID: 701670 • Letter: 1
Question
1. The boiler produces saturated vapor at 285 K and 0.02MPa 2. The compressor has an efficiency of 70% 3. The condenser produces saturated liquid at 305 K and 0.09 MPa. The refrigerant is propane. Assuming propane behaves as an ideal gas, estimate the coefficient of performance.ulx D: Heat Capacity D.1 Ideal Gas Heat Capacity The coefficients in the table below are used to compute t of a compound as a function of temperature, throug where T is expressed in Kelvin. The coefficients were obtain which includes a much more extensive list of compounds. A + BT + CT2 + DT' + ET" e coefficients were obtained from Poling (2001). Name Chlorodifluoromethane (R-22) Methane Methanol Carbon monoxide Carbon dioxide Ethylene (Ethene Ethane Ethanol Formula B×10, Cx 10 Dx 10 E x 10" 3.164 10.422 1.179 1.222 50-1000 4.568 -8.975 -6.986 -3913 1091 1.535 0.515 50-1000 50-1000 50-1000 3.631 -3407 CH Co Co 4.714 4.443 4.211 3.912 3.259 4.221 4.178 1.182 1.302 -2.374 6.792 6.651 50-1000 .356 8.782 4.427 1.502 5.795 5.660 2.511 50-1000 GH 2.487 50-1000 50-1000 50-1000 200-1000 -7024 0.628 3.893 1.511 5.131 4.396 CH 4.688 -6.013 3.834 2.728 5.731 6.011 6.310 5.126 Propanone (Acetone) 50-1000 -7.893 3.079 3.847 4.712 3.607 4.389 50-1000 Propane 3.216 6.565 50-1000 5.321 3.165 8.253 -12.371 5.085 50-1000 -8.197 1,3-Butadiene 6.143 7.984 10 57 1-Butene
Explanation / Answer
The coefficiant of perfomance is the ratio of heat supplied/removed by the system to the work required by the system.
Here in this example for a refrigerator with respect to propane refrigerant for cooling system is 285K,
work required is 305-285=20K
now,the COP is given as 285/20=14.25.
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