1. What is the total kinetic energy of 0.5 mol of an ideal monatomic gas confine
ID: 701330 • Letter: 1
Question
1. What is the total kinetic energy of 0.5 mol of an ideal monatomic gas confined to 5.0 dm^3 at 150 kPa?
2. Compare the pressures predicted for 0.6 dm^3 of Cl2 weighing 18.5 g at 298.15 K using the ideal gas equation and the Van der Waals equation.
3. A sample of liquid acetone weighing 0.700 g was burned in a bomb calorimeter for which the heat capacity (including the sample) is 6937 J/K. The observed temperature rise was from 25.00 °C to 31.50°C. Calculate U and H for the combustion of 1 mol of acetone.
Explanation / Answer
Ans 1
Moles n = 0.5 mol
Volume V = 5 dm3
Pressure P = 150 kPa
From the concepts of Kinetic Theory of Gases
P = Nmu2 / 3V
Average Kinetic energy = 0.5 mu2
At constant pressure
V is proportional to n and Average Kinetic energy
N = n x L
From the above equations
PV = (2/3) x n x L x average kinetic energy
Total kinetic energy = L x average kinetic energy
PV = (2/3) x n x total kinetic energy
total kinetic energy = 1.5 PV/n
= 1.5 x 150 x 5 /0.5
= 2250 J/mol
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