1. (a) for the formation of 1 mol of liquid water, H 2 (g) + 1/2 O 2 (g) -------
ID: 700721 • Letter: 1
Question
1.
(a) for the formation of 1 mol of liquid water,
H2 (g) + 1/2 O2 (g) ---------------> H2O (l) , deltaH = - 572 / 2 = - 286 kJ/mol
(b) For the dissociation of water,
H2O (l) ------------> H2 (g) + 1/2 O2 (g) , delta H = + 286 kJ
2.
N2 (g) + 3 H2 (g) --------> 2 NH3 (g) , delta H = - 91. 8 kJ
From the balanced equation,
formation of 2 * 17 = 34 g. of ammonia gives 91.8 kJ of heat
then,
formation of 9.07 * 105 g. of ammonia gives = 9.07 * 105 * 91.8 / 34 = 2.45 * 106 kJ
3.
Heat change = mass * specific heat * change in temperature
q = 15.0 * 4.194 * (50 - 20)
q = 1882.8 J
q = 1.88 kJ
Explanation / Answer
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