The mass of MMA = 1 g The molar mass of MMA = 86 g/mol Therefore, the no. of mol
ID: 700569 • Letter: T
Question
The mass of MMA = 1 g
The molar mass of MMA = 86 g/mol
Therefore, the no. of moles of MMA = 1/86 = 0.0116 mol
The mass of styrene = 1 g
The molar mass of styrene = 104 g/mol
Therefore, the no. of moles of styrene = 1/104 = 0.0096 mol
The mass of AIBN = 0.02 g
The molar mass of AIBN = 164 g/mol
Therefore, the no. of moles of AIBN = 0.02/164 =0.0001 mol
The observe PDI of the solution = 1.11
Theoretical PDI of the reaction = 1.5 (coupling reaction)
= 2.0 (disproportionation)
Explanation: The observed PDI (1.11) of the solution is less than that of the theoretical PDI (1.5 to 2).
Most probably, there happened an alternating copolymerization between MMA and styrene, having almost the same units of MMA as well as styrene, resulting in the PDI ~ 1 (1.11).
Explanation / Answer
Radical copolymerization of MMA 1.000 g and styrene 1.000 g occured in toluene solution(18 mL) and initiator is AIBN(0.020 g)
Solution was purged with N2 gas.
What was happened if PDI of this solution is 1.11?
Theoritical PDI of this reaction is 1.5 to 2.0(disproportionation = 2.0, coupling reaction = 1.5)
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