step 1: Assume 100 g of the compound is present. This changes the percents to gr

Question

step 1: Assume 100 g of the compound is present. This changes the percents to grams:

C 57.48 g

H 4.22 g

O 38.29 g

Step 2:

Convert the masses to moles:

C 57.48 g /12.01g/mol=4.786 mol

H 4.22 g /1.01=4.178 mol

O 38.29 g/16g/mol=2.393mol (Smallest)

Step 3:

Divide by the lowest, seeking the smallest whole-number ratio:

C 4.786/2.393=1.999=2 (rounded nearest whole no)

H 4.178/2.393 =1.76

O 2.393/2.393=1

Further the above moles need to multiply the above with 4 to give all whole numbers.

If this is done we get

C=2*4=8

H=1.76*4=7.04 =7(rounded nearest whole no)

O=1*4=4

step 4:

write the molecular formula

Therefore the empirical formula is C8H7O4

Explanation / Answer

) 10.0D) 33.2 he mass percentages in a compound are carbon,57.48%, hydrogen 4.22%and oxygen 38.29%, what is pirical formula? (A) C,H,O (C) CH,O2 (B) CH,O (D) C,HO 6 12 .18 , 4.2c 414 ,14

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.