Zn(s) ----------------------> Zn^2+ (aq) + 2e^- E0 = 0.733v Cu^2+ (aq) + 2e^- --

Question

Zn(s) ----------------------> Zn^2+ (aq) + 2e^-                E0 = 0.733v

Cu^2+ (aq) + 2e^- ---------> Cu(s)                                E0 = 0.367v

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Zn(s) + Cu^2+ (aq) ----------> Zn^2+ (aq) + Cu(s)        E0cell = 1.1v

    n = 2

Ecell    = E0cell - 0.0592/n logQ

            = 1.1-0.0592/2 log[Zn^2+]/[Cu^2+]

            = 1.1-0.0296log0.3/0.1

             = 1.1-0.0296*0.4771

               = 1.086V >>>>answer

Explanation / Answer

alculate Ecell for the following voltaic cell reaction, Zn(s) Cu2+(0.100 M) + Cu(s) + Zn2+(0.300 M), Eeuan cu = 0.367 v, Ebonza Zn()Zn-0.733 v ncentration

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