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2(i). Compresibility factor of a gas is a correction factor by which we can meas

ID: 700019 • Letter: 2

Question

2(i). Compresibility factor of a gas is a correction factor by which we can measure the deviation of a real gas from an ideal gas. It is defined as the ratio of the molar volume of a gas to the molar volume of an ideal gas at the same temperature and pressure. Now molar volume of the real gas is 22.8 L/mol (given) and at the same condition the molar volume of the ideal gas is 24.5 L/mol(given).

Therefore, the compresibilty factor (z) is = molar volume of gas/molar volume of ideal gas

= 22.8/24.5 = 0.93 < 1

So, the Answer is (c) less than 1.

(ii) In statistical mechanics, z=pV/nRT

where where p is the pressure, n is the number of moles of gas, T is the absolute temperature, and R is the gas constant. When pressures are lower, the molecules are free to move. In this case attractive forces dominate, making z < 1. Since you have z < 1, the attractive force dominated. Ans (a)

Please note if z > 1, repulsive force predominates

z =1, no molecular interaction (ideal gas)

(iii) The equation for the ideal gas is given as

p = RT/(Vm - b)

or, pVm - pb = RT

or pVm/RT - pb/RT =1

or pVm/RT = 1+pb/RT

Compairing with the virial form, pVm/RT = 1+BP, we have

B = b/RT > 1

Ans . (c)

Hope this will help. Cheers!!

Explanation / Answer

2. The molar volume of (same pressure and (i) (3pt) The com emperature). The real gas has the molar heat capacity c." (a) greater than 1 is 245 L/mol at the same condition our calculation or explanation a real gas is 22.8 /mol and the molar volume of the ideal gas compression factor Z of the above real gas should be (b) equal to 1 (c) less than 1 (d) unable to be justified () (3pt) The intermole (a) attractive forces (b) repulsive forces cular interaction of the above real gas should be dominated by (no explanation needed) (c) no molecular interaction a real gas has the equation of state: p . RT/N--b) (b: van der Waals parameter related to the size of gas molecules; b

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