C2H2 + 2 Cl2 --> C2H2Cl4 no of moles of C2H2 = W/G.M.Wt = 7.054/26 = 0.27 moles

ID: 699941 • Letter: C

Question

C2H2 + 2 Cl2 --> C2H2Cl4

no of moles of C2H2 = W/G.M.Wt

= 7.054/26 = 0.27 moles

no of moles of Cl2 = W/G.M.Wt

= 44.65/71 = 0.63moles

2moles of Cl2 react with 1 mole of C2H2

0.63 moles of Cl2 react with 0.63*1/2 = 0.315 moles of C2H2

C2H2 is limiting reactant

1 mole of C2H2 react with Cl2 to gives 1 mole of C2H2Cl4

0.27 moles of C2H2 react with Cl2 to gives 0.27 moles of C2H2Cl4

mass of C2H2Cl 4 = no of moles * gram molar mass

= 0.27*168 = 45.36g of C2H2Cl4 >>>>answer

How many grams of C2H2Cl4 can be prepared by reaction of 7.054 g of ethyne (C2H2) with 44.65 g of chlorine (Cl2)?

C2H2 + 2 Cl2 --> C2H2Cl4

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