NH4OH is weak base Kb = 1.8*10^-5 NH4OH --------------------> NH4^+ (aq) + OH^-
ID: 699784 • Letter: N
Question
NH4OH is weak base
Kb = 1.8*10^-5
NH4OH --------------------> NH4^+ (aq) + OH^-
I 0.3 0 0
C -x +x +x
E 0.3-x +x +x
Kb = [NH4^+][OH^-]/[NH4OH]
1.8*10^-5 = x*x/0.3-x
1.8*10^-5 *(0.3-x) = x^2
x = 0.0023
[OH^-] = x = 0.0023M
POH = -log[OH^-]
= -log0.0023
= 2.6383
PH = 14-POH
= 14-2.6383
= 11.3617 >>>>>answer
Explanation / Answer
Calculated pH of a solution that contains 0.30 M NH4OH Calculated pH of a solution that contains 0.30 M NH4OHRelated Questions
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