Na 2 SO 4 (aq) + AgNO 3 (aq) Ag2SO4(s) + 2NaNO3(aq) no of moles of Na2So4 = W/G.
ID: 699745 • Letter: N
Question
Na2SO4 (aq) + AgNO3 (aq) Ag2SO4(s) + 2NaNO3(aq)
no of moles of Na2So4 = W/G.M.Wt
= 17.5/142 = 0.123 moles
no of moles of AgNO3 = W/G.M.Wt
= 29.4/170 = 0.173 moles
1 mole of AgNO3 react with 1 mole of Na2SO4
0.173 moles of AgNO3 react with 0.173 moles of Na2SO4
Na2SO4 is limiting reactant
1 mole of Na2SO4 react with AgNO3 to gives1 mole Ag2SO4
0.123 moles of Na2SO4 react with AgNO3 to gives = 1*0.123/1 = 0.123 moles of Ag2SO4
mass of Ag2SO4 = no of moles * gram molar mass
= 0.123*311.8 = 38.35g of Ag2SO4 >>>>>answer
Explanation / Answer
A reaction will occur for the following in aqueous solution. This means that an insoluble product will be formed, but only one of the products is insoluble.
Na2SO4 (aq) + AgNO3 (aq) ?
If 17.5 g of Na2SO4 and 29.4 g of AgNO3 are reacted, what mass of the insoluble product is formed?
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