Raoult\'s Law tells us that in an ideal solution, the vapour pressure of a compo
ID: 699651 • Letter: R
Question
Raoult's Law tells us that in an ideal solution, the vapour pressure of a component is proportional to the mole fraction of that component in solution.
Mole fraction of sucrose: =Moles of sucrose/ Moles of sucrose + moles of water
MW (C12H22O11) = 12*12 + 22*1 + 11*16 = 342 g/mol
MW (H2O)= 1*2+16=18g/mol
sucrose=2x10^2g/342.13gmol/2x10^2.g/342.13gmol/3.50x10^2/18.01gmol
= 0.584/20.024
=0.029
The number of moles in the mixture= 3.50x10^2/18 +2.00x10^2/342
=19.44+0.584
= 20.024
Mole fraction of water:
water=3.50x10^2g/18.01gmol/2x10^2g/342.13gmol/+350x10^2g/18.01gmol
=19.44/20.024
=
Note that by definition, sucrose+water=1
Because sucrose is involatile, the vapour pressure of the solution is proportional to the mole fraction of water:
Psolution=water×17.5mmHg
=0.9708×17.5mmHg
=16.98.mm.Hg
0.9708
Explanation / Answer
2. The vapor pressure of water at 20°C is 17.5 mmHg. What is the vapor pressure of water over a solution prepared from 2.00x 10 g of sucrose (C12H22011) and 3.50 x 10 g water?
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