Suppose the human trait for hair type is controlled by a simple dominant and rec

Question

Suppose the human trait for hair type is controlled by a simple dominant and recessive relationship at one locus. Curly hair, C, is the dominant allele, and straight hair, c, is the recessive allele. In a college genetics class, the professor takes a tally of the number of students who have curly hair and those with straight hair. In this class of 117 students, 37 have curly hair. Calculate the frequency of the dominant allele, C, and the heterozygous genotype, Cc. Express the frequencies in decimal form rounded to the nearest thousandth. Assume the class is in Hardy–Weinberg equilibrium for this trait.

Explanation / Answer

The frequency of curly hair is 37 out of 117 which is 31.62 % (37/117 x 100)

Which means p2 = 0.31; p - 0.55

p+q = 1

q = 1-p

q = 0.45

q2 = 0.2025, p2 = 0.31, 2pq - 2(0.55)(0.45) = 0.495

The frequency of curly hair CC - p2 - 0.31

The frequency of curly hair Cc - 2pq = 0.495

The frequency of straingh hair cc - q2 - 0.2025

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