6) Hydrogen gas can be generated from the reaction between aluminum metal and hy
ID: 699198 • Letter: 6
Question
6) Hydrogen gas can be generated from the reaction between aluminum metal and hydrochloric acid: 2 Al (s) + 6HCI (aq) 2 AIC, (aq) + 3H2 (g) a. Suppose that 3.00 grams of Al are mixed with excess acid. If the hydrogen gas produced is directly collected into a 850. mL glass flask at 24.0 °C, what is the pressure inside the flask (in atm)? This hydrogen gas is then completely transferred from the flask to a balloon. To what volume (in L) will the balloon inflate under STP conditions? b. Suppose the balloon is released and rises up to an altitude where the temperature is 11.2 °C and the pressure is 438 mm Hg. What is the new volume of the balloon (in L)? c. Page 3 of 3Explanation / Answer
2Al(s) + 6HCl(aq) -----> 2AlCl3(aq) + 3H2(g)
2 moles of Al react with excess of HCl to gives 3 moles of H2
2*27g of Al react with excess of HCl to gives 3 moles of H2
3 g of Al react with excess of HCl to gives = 3moles*3g/2*27g
= 0.166 moles of H2
n = 0.166 moles
V = 850ml = 0.85L
T = 24+273 = 297K
PV = nRT
P = nRT/V
= 0.166*0.0821*297/0.85 = 4.76atm
b.
experimetal conditions STP conditions
P1 = 4.76atm P2 = 1atm
V1 = 0.85L V2 =
T1 = 297K T2 = 273K
P1V1/T1 = P2V2/T2
V2 = P1V1T2/T1P2
= 4.76*0.85*273/297*1
= 3.72L >>>>.answer at STP conditions
c.
STP conditions new conditions
P1 = 1atm = 760 mmHg P2 = 438mmHg
V1 = 3.72L V2 =
T1 = 273K T2 = 11.2+273 = 284.2K
P1V1/T1 = P2V2/T2
V2 = P1V1T2/T1P2
= 760*3.72*284.2/273*760 = 3.87L >>>>answer
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.