I need help answering this please! Thank you! The data below were collected for

Question

I need help answering this please! Thank you!

The data below were collected for an enzyme-catalyzed reaction ISl (mM) 0.20 0.33 2.00 4.00 This graph is provided for your use only. It will not be graded. (It is not necessary to use a graph to answer.) 0.86 1.20 2.42 2.69 Click on the graph to activate the Tools menu Choose "Point," and then click a place oin the graph to place the point To move a point, choose "Select," and then drag the point Use "Select" to scroll over a point to see its coordinates, or to see the equation of a line .Use the option "Line" to draw a line 0.6 Determine Vmax and Km for this reaction Number mM s 0.2 max Number 0.0 2 1 012 3 4 5 K, Im

Explanation / Answer

Lineweaver- berk plot is

1/V= (KM/Vmax)*1/S + 1/Vmax

so a plot of 1/V vs 1/S gives straight line whose intercept is 1/Vmax and slope is KM/Vmax

The plot along with the data points is shown below.

From the plots, 1/Vmax= 0.2754, Vmax= 1/0.2754 mM/s =3.63 mM/s and slope is KM/Vmax= 0.2314

Km= 0.2314* 3.63=0.84mM

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