QUESTION 11 For the equilibrium reaction H3PO4 + OH? H2PO4 + H20, what is the co

Question

QUESTION 11 For the equilibrium reaction H3PO4 + OH? H2PO4 + H20, what is the correct descri O a. A conjugate acid-base pair is H3PO4 and H2O O b. The reaction will not occur because the strong base OH is favored. O c. The stronger acid is H3PO4 so the reaction will proceed forward O d. Water is acting as a base in the reverse reaction. QUESTION 12 In which of the following reactions will the forward reaction be favored if pressure is inc O a. Si (s) + 2 Cl2 (g) SiCl4 (g) O b, C (s) + H2O (g) CO (g) + H2 (g) O c. 2 CO2 (g)2 CO (g) + 02 (9) O d. N2 (g) + O2 (g) NO2 (g) QUESTION 13 What is the hydronium ion concentration of a solution with a pH of 6.0? O a.6 x 101 M O b 1 x 100 M Oc-6x10-14 M O d. 1 x 10° M

Explanation / Answer

an acid when looses proton becomes conjugate base. A base when gives proton becomes an acid.

H3PO4 is an acid and looses proton to become H2PO4- and H2O is an acid and loose proton to give a base of OH-

The reaction will not occur because H3PO4+ H2O-------> H2Po4-+ H3O+ is the correct reaction, ( B is the correct answer)

2. As per Lechatlier principle, when pressrue is increased at constant temperature, as per gas law, PV=nRT

there will be an increase in moles. the reaction proceeds so to as compensate the effect of increased pressure, so the reaction proceeds in a direction of decrease in moles of gases.

In the reactions given, 1st reaction, there is a decrease in no of moles of gases, product gas moles =1 and reactant gas moles=2, moles difference= -1. So there is a decrease in moles. This reaction is favored.

for reaction-2, mole difference of products and reactant gases= 1+1-1=1 for reaction-3, moles difference = 2+1-2=1, for 4th reaction, moles difference (N2+2O2----->2NO2), mole difference= 2-1-2=-1, So this is also favored.

Reactions-1 and 4 are favored by increased pressure.

3. given pH= 6

pH= -log [H3O?+]=6

[H3O+]= 1*10-6, B is correct.

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