13) The reaction below shows the oxidation of sulfur dioxide to form sulfur trio

Question

13) The reaction below shows the oxidation of sulfur dioxide to form sulfur trioxide. 2 SO, + O, 2 SO3(g) aH @sc=-197.6 kJ In the laboratory, SO2 and O2 gases are placed inside a sealed container and allowed to react at 250°C. At equilibrium, the concentrations are found to be [SO2]-1.3 M, [O]-5.3 M and [sO,]-12 M. Based on this information, predict the value of the equilibrium constant for this reaction when it occurs inside the cone of a volcano at a temperature of 1327 °C. (10pts) Ti i 327°C+ 273

Explanation / Answer

Kc = [SO3]^2/[SO2]^2[O2]

   = 1.2^2/(1.3^2*5.3)

kC = 0.16 at 25 C

DG0 = -RTlnKc

    = -8.314*298ln(0.16)

   = 4.54 kj/mol

DG0 = DH0-TDS0

4.54 = (-197.6)-(298*X*10^-3)

X = DS0 = -678.32 j/mol.k

at T = 1327 c = 1327+273.15 = 1600.15 k

DG0 = DH0-TDS0

   = (-197.6)-(1600.15*-678.32*10^-3)

   = 887.8 kj/mol

DG0 = -RTlnKc

887.8*10^3 = -8.314*1600.15ln(x)

x= Kc = 1.04*10^-29

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