T) Refer to the galvanic cell below (the contents of each half-cell are written
ID: 698281 • Letter: T
Question
T) Refer to the galvanic cell below (the contents of each half-cell are written beneath each 15 pts 1.0 x 103 MN 10 MHC 1.0MHCI AgC(s) The Standard reduction potentials are as follows. Ag+ + e-Ag(s) Eo = 0.30 V Ni2 + 2e-Ni(s) E=-0.23 V i) Calculate the standard cell potential E ii.) Write the net cell reaction. ii) What is the value of Q, the reaction quotient, for this cell reaction? Note Kp for Agci- 1.6 × 10-10 and the Ag+ in equilibrium with AgCl(s). iv.) What is the cell potential E at 25°C for this cell as read on the digital voltmeter? v) Calculate the free energyExplanation / Answer
(i)
E0cell = 0.80 - ( - 0.23 ) = 1.03 V
(ii)
Cell reaction is,
Ni (s) + 2 Ag+ (aq.) ------------> Ni2+ (aq.) + 2 Ag (s)
(iii)
Ksp of AgCl = [Ag+][Cl-]
Ksp = S2
S = sqrt.Ksp = sqrt.(1.6*10-10) = 1.26 * 10-5 M
Q = [Ni2+] / [Ag+]2
Q = 1 * 10-3 / (1.26 * 10-5)
Q = 62.5
(iv)
Ecell = E0cell - (0.0591 / n) * LogQ
Ecell = 1.03 - (0.0591 / 2) * Log(62.5)
Ecell = 0.977 V
(v)
deltaG = - n F Ecell = - 2 * 96500 * 0.977 = - 188561 J = - 188.6 kJ
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