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please show work. thank you! 27. The ionization constant of water at a temperatu

ID: 698268 • Letter: P

Question

please show work. thank you!

27. The ionization constant of water at a temperature 20°C is 6.807 × 10-15 what is the pH of pure water at this temperature? (3 pt) mtle2 28. A 0.015 M solution of a weak acid has a pH of 3.52. What is the value of the Ko for this acid (3 pt)? 29. What is the pH of a 0.041 M HCI solution? (3 pt)* water?(% for whete bolng point of a solution of 0.92 g of glycerol, CaHk0, (MM-92.09 g/mol), in 20,0 g of water? (Kb for water = 0.512 °C kg/mol) (3 pt)" M-92.09 g/mol), in 20.0 g of 31. what volume of 0.80 M HCl will be required to titrate a 20.0 mL solution of 0.50 M NaOH to the equivalence point (3 pt)*

Explanation / Answer

27)

Kw = 6.807*10^-15

now use:

Kw = [H+][OH-]

since water is neutral,

[OH-] = [H+]

So,

Kw = [H+][H+]

6.807*10^-15 = [H+]^2

[H+] = 8.25*10^-8

Now use:

pH = -log[H+]

= -log(8.25*10^-8)

= 7.08

Answer: 7.08

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